4x^2-92x+480=-4x^2+92x

Solution for 4x^2-92x+480=-4x^2+92x equation:

4x^2-92x+480=-4x^2+92x

We move all terms to the left:

4x^2-92x+480-(-4x^2+92x)=0

We get rid of parentheses

4x^2+4x^2-92x-92x+480=0

We add all the numbers together, and all the variables

8x^2-184x+480=0

a = 8; b = -184; c = +480;
Δ = b2-4ac
Δ = -1842-4·8·480
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-184)-136}{2*8}=\frac{48}{16}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-184)+136}{2*8}=\frac{320}{16}
=20
$